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Monday, September 30, 2019

Speed and distance time Math

Time distance and speedHello viewers I that hope that all fine. Discussion for today how to math solution easy to succeed. Our how to knowledge can't math solution. As a result just fail any exam I think that math very simple and easy.we are think that math is heart As a result any exam fail.
              why don't math solution us.?
     A special point every person thinking is
     Math very heart it's very tension we are
     No tension just think very simple and
     Easy.
               How do think math solution?
(1) Yousef think math is very simple
(2) No tension math is very simple and easy.
(3) math will be try everyday day to night
    two hours.
(4) tension is very sad because fail the exam
(5) not fear of math I confidential can it .
(6) it need point of math regular try so
      successful exam
So hello viewers move on any examples
Today do it Relative speed job example
                             speed
Speed = distance/ time     
Avareg speed= distance/ time
⇛   A train lift from kh  station45 after kha stopped of station. Two station distance 85 km . But how to Avareg speed of two train?
Example :  1 hours = 60 minute
 1.   ,,.    ,,       ,,. 84/45. ,,
,, 60  ,,.   ,,.     ,, 84×60/45 = 112 km answer
⇛   A car speed per second 60 ft. How to speed per hours?
Example : 1 second gone = 60 ft.
1 hours or ( 60×60) second gone ( 60×60×60)
                       = ( 60×60×60)/3×1760
                       = 40.9 mile answer
⇛A train 46 minute A town from B town arrived . Two town distance 59.8 mile how to speed the train per hours?
Example : 46 minute gone = 59.8 mile
1.         ,,.      ,,.  59.8/46 mile
60       ,,.       ,,.  59.8×60/46
                      = 78 mile
⇛Distance of Chittagong to Dhaka 265 km a bus has arrived 7 hours  Rasthayto Khulna
A bus stopped 1 hours in a Road . how to Avareg speed s bus ?
Example : A bus speed =  distance/time
                      = 275/5 km
                      = 53 km.
⇛ distance of Rajshahy to Khulna 282 km. A bus has arrived 7 hours . But a bus stopped 1 hours how to Avareg speed a bus per hour?
Example :  bus move on = (7-1) = 6 hours
Avareg speed of bus = 282/6 km
                                      = 47 km Answer
⇛ A speeder speed of fevareble 1 hours 3 mile . And starting point of back . How to speed per hours?
Example : distance = (3+3) mile
                                   =  6 mile
Cost Tim.                  = ( 1+3)
                                   = 4 hours
Avareg speed.          = 6/4 mile. = 1 -1/2  mile

⇛ A speeder speed of fevareble 2 hours he gone 5 mile. And he back to 4 hours. But how to traveling Avareg speed per hour?
Example : distance = (5+5) mile
                                    = 10 mile
Cost time                   = (2+4)
                                    = 6 hours
Avareg speed           = distance/ time
                                   = 10/6 mile
                                   = 5/3 mile
                                   = 1-2/3 Answer
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Thanks everybody.

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