Speed and distance time Math

Time distance and speedHello viewers I that hope that all fine. Discussion for today how to math solution easy to succeed. Our how to knowledge can't math solution. As a result just fail any exam I think that math very simple and easy.we are think that math is heart As a result any exam fail.

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Today do it Relative speed job example
                             speed
Speed = distance/ time     
Avareg speed= distance/ time
⇛   A train lift from kh  station45 after kha stopped of station. Two station distance 85 km . But how to Avareg speed of two train?
Example :  1 hours = 60 minute
 1.   ,,.    ,,       ,,. 84/45. ,,
,, 60  ,,.   ,,.     ,, 84×60/45 = 112 km answer
⇛   A car speed per second 60 ft. How to speed per hours?
Example : 1 second gone = 60 ft.
1 hours or ( 60×60) second gone ( 60×60×60)
                       = ( 60×60×60)/3×1760
                       = 40.9 mile answer
⇛A train 46 minute A town from B town arrived . Two town distance 59.8 mile how to speed the train per hours?
Example : 46 minute gone = 59.8 mile
1.         ,,.      ,,.  59.8/46 mile
60       ,,.       ,,.  59.8×60/46
                      = 78 mile
⇛Distance of Chittagong to Dhaka 265 km a bus has arrived 7 hours  Rasthayto Khulna
A bus stopped 1 hours in a Road . how to Avareg speed s bus ?
Example : A bus speed =  distance/time
                      = 275/5 km
                      = 53 km.
⇛ distance of Rajshahy to Khulna 282 km. A bus has arrived 7 hours . But a bus stopped 1 hours how to Avareg speed a bus per hour?
Example :  bus move on = (7-1) = 6 hours
Avareg speed of bus = 282/6 km
                                      = 47 km Answer
⇛ A speeder speed of fevareble 1 hours 3 mile . And starting point of back . How to speed per hours?
Example : distance = (3+3) mile
                                   =  6 mile
Cost Tim.                  = ( 1+3)
                                   = 4 hours
Avareg speed.          = 6/4 mile. = 1 -1/2  mile

⇛ A speeder speed of fevareble 2 hours he gone 5 mile. And he back to 4 hours. But how to traveling Avareg speed per hour?
Example : distance = (5+5) mile
                                    = 10 mile
Cost time                   = (2+4)
                                    = 6 hours
Avareg speed           = distance/ time
                                   = 10/6 mile
                                   = 5/3 mile
                                   = 1-2/3 Answer
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Relative speed Math solve

Relative speedOnline teach for job preparation of math Relative speed ( part 2)

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taking about Relative speed how to solution train or car math example solution. So viewers hope that on my site very successful in our students life and job examination. Don't worry math solution Relative speed no heart very simple very  easy . Just we have to bad tension Very simple .so Don't more talking now  move on details Relative speed example solution . Okay viewers .
1/ Distance Dhaka to Chittagong 185 mile. By a bus from Chittagong per hours 2 hours and 85 mile going to 100 mile . how to speed by bus 50 km.?
⏩Answer : going to Dhaka fromChittagong  needed time t = distance/time = 185/50 = 3.7
85  mile 2 hours going to = (3.7-2) hours
        = 1.7 per hours = ( 1.7×60) = 102 minute
2/ A car speed per hour 25 mile.runing Chittagong from Dhaka.  Another A car speed per hour running Dhaka from Chittagong . Dhaka to Chittagong distance 200 mile. How to running between car After time face to face between car?
⏩Answer : when two car running opposition side
Therefore there Relative speed per hour
 ( 25+15)=  40 mile.
1  hoursspeed go on 40 mile
1   ,,    ,,    1/40
200    ,,     200/40 = 5 hours.
3/ traveling to fast 6 hours Avareg speed 40 km. And second position Avareg speed 60 km. If complete  traveling to car Avareg 55 km. how to traveling time is?
⏩Answer : the car traveling time = t .
       The cat crossing t hour 55 km.
       The car crossing 6 hour =
                       (40×60)=240km
The car (t-6) crossing per hours
                           =  60( t-6) km
Condition apply 240+60( t- 6) = 56 t
Or 240 +60 t - 360 = 55 t
Or 5 t = 120

So t = 24 minute .
4/ house of Karim from Dhaka distance to 356 k.m. he has gone from Dhaka 319 km After bus is out of command so going to by Rickshaw. The speed of bus 22 km. Per hour. And Rickshaw speed 6 km. Per hour. So how did time arrive korim of house?
⏩Answer : Karim go to by bus 319 km
                    By Rickshaw ( 355-319)
                                             = 36 km.
                    Time = distance/ speed
By bus.       = 319/22 = 14 hour 30 minute
By Rickshaw= 36/22 = 6 hours.
Arrive to home time = 14 hour 30 minute+6 hour = 20 hours 30 minute.
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Relative speed train Math suggestions

Speed

Online math preparation Relative speed ( train)

we Done relative speed by train. Relative speed very simple and easy solution. So viewers we will try train speed how to knowing Relative speed solution. So

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                        Relative speed

Suppose between two train speed  u and v(>v)

1/ When  two car or between train move on opposite then Relative speed both equal .

         Relative speed = u+v

2/ when two car or train move on same side then Relative speed  = u-v

         Calculation the speed of a train

A signals post crossings x length and needed t time 

                A train t time crossings x mitres

So ,,      ,,       ,,   X/t

          Train speed = x/t

Y length a object ( when pull and hole, platform.) Others stand a car x length  needed t time .  

A train t time crossings (x+y). metre Dist.

Metres    ,,    ,,   ,,  x+y/t

                      Example solution

We Done example solution Relative speed A train. Okay . 

1 / A train speed per hour 60 metre how do time crossings A lamp post  100 metre train?

Answer:     1 hours = (60×60) second

                   60 km     = (60×1000) metre

(60×1000) crossings time (60×60) second.

1   ,,    ,,    ,,    ,,  60×60/60×100

100    ,,    ,,    ,,  60×60×100/60×1000

       

   Answer 6 second.

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2/ 50 metres length A train speed per hour 36 km. How do crossings time the train a lamp post ?

Answer: 36 km  =  (36× 1000) metre =3600 m

1 hour (60×60) = 3600 second.

The train crossings a post and self length 

          36000 metre needed time 3600 second

1            ,,     ,,    ,,   ,,   3600/36000

50         ,,     ,,    ,,    ,,   3600×50/36000

            Answer 5 second.

3/ it hase a plam tree a side on railline . Per hour continue a train speed 45km . The train length is 150  how do crossings time this plam tree?

Answer :  (45×1000) metre =45000 metre.

1hour = (60×60) = 3600 second

The train crossings and plam tree 45000 m

3600 second.

     1.  ,,     ,,    ,,   3600/45000

   150 ,,    ,,    ,,   3600×150/45000

              Answer = 12 second.

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