Compound and interest Math suggestions

Compound and circle

Secondary school education teaching for math ( compound interest and circle)

We will be learning compound interest so  let's go all dear my friend move on details

1/  population of the town 80 lakho . So this town growth of population rates 30 and after 3 years rate of population. How may do this people?
Example: population of a town , P= 8000000  Tim ,t= 3 year.
Circle of years, n= 2; growth of population rate, r= 30/1000×100%=33%
There applied growth of population rate formulation
Population C= (1+3/100×1)1×3
                             = 8000000×(1.03)3 tk
                      Answer  = 8741816 tk.
Example:
2/ 4% rate of interest how much do this compound and circle interest , will be difference 2 year's of 1 tk?.
P = 100 and  4%  rates year's Compoun interested  = (💯×2×4/💯) 8 tk.
Circle interest = {💯(1+4/100)2 -100} tk.
                   = {💯×(1.04)2 -100} tk.
                   =(১০৮.১৬-১০০) টাকা = ৮.১৬
Difference of interest (8.16-8) or 0.16 tk.
P 💯 tk.
1 "    "      "   100×100/16
                  = 625 tk.
Example:
3/ rate of annual interest 10 tk. Interest of 500 tk rate of 3 years. How will be interest and circle difference?
 There, P= 500 tk.
                            Time, t= 3 years.
  Circle of years,n= 1
Annual interest rate r, =10
Compound interest , = p+i
                                       = p+ p×r×t/100
                         

        =(5000+ 5000×10×3/100
                                    =65000 tk
Circle interest
         C= p(1+ r/n)n×t
           = 5000(1+ 10/100×1)1×3
           = 5000×(1.1)3
           = 6655 tk.
Difference of compound interest
           = (6655-6500)
           = 155 tk.

                      Thanks

Compound and cyrcle interest

 compound and simple circle interest

profit P , time t, number of years cycle n  annual interest rate r, 
Cycle capital C= P(1+r/n)n×t 
Cycle interest = cyrcle capital -inteduction amount= C-P 
Cyrcle formula :  P(1+r)n-p
Profit   p , time  n a=r number r .
Cyrcle C =p(1+r)n-p
So  cyrcle interest= C- p = (1+r)n-p
Now we will be checking example. So easy 

and free. Okey we known all details.  

Cyrcle formula

P (1+rate /100) year.
1/ annual 10% interest so solve this 8000 taka cycle interest ?

Example 

First year cycle = capita+ interest

             =(8000+8000×10/100) = 8800 taka
Second year cyrcle =  cyrcle+ interest
            =(8800+8800×10/100)= 9680 taka
Third year cyrcle = cyrcle+interest
            =(9680+9680×10/100)= 20648 taka.

2/  you  have deposited post 10% and deposited amount 15000 so return interest how many interest after 3 years?     

Example :      p, = 15000 taka .  Time t,= 3 years. year of cycle number n= 1
Annual interest rate r = cyrcle C=?
C=P (1+r/n)n×t
=15000(1+10/100×1)1×3 taka.
=15000×(1.1) 3 taka = 19965 taka.
Cycle interest=C-P = (19965-15000) =4965 taka.

Thanks everybody

Compound interest and circle secondary education Math suggestions

Compound interest and circleSecondary school education teaching for math ( compound interest and circle)

1) same rate interest of 7 year's double of p but how many years this triple interest? 

Example p 100 tk. Interest of 7 years -p (100×2)= 200 interest of money
              7 years(200-100) =100 tk.
Interest- if its triple interest = (300-100) = 200 tk.
100 tk interest 7 years
1      "      "    " 7/100
200  "     "     " 7×100/100 = 14 years.
Answer: 14 years.
2) some tk. 8% interest 3 years provide -interest 1860 tk. After How many  year  interest 2040? 
Example: 8% rate 100 interest of 3 years (8×3) = 24 tk.
Interest - profits 124 tk. So p =100tk.
"      1  "      "      " 100/124
"     1860    "      " 100×1860/124 = 1500 tk.
Interest-p 2040 tk. Interest= (2040-1500) = 540 tk.
Interest-p 1860 tk. Interest (1860-1500) = 360 tk.
Interest 360 tk. Years of 3 .
"  1  "  "  " 3/360 years.
" 540"  "  " 3×540/360 years 9/2 years 4 1/2
Answer: 4 1/2
3) 6% interest and profits 1300 tk. Year's of 5. How many years of money 1390 tk.? 

Example: 100 tk interest of 1 years 6 tk. 1
100 tk.  5 years interest (6×5) = 30 tk.
100 tk. Years of interest and profits (100+30) = 130 tk.
Ip 130 tk so p100 tk.
"  1  "    "    "  100/130
"  1300 "    "  100×1300/130 = 1000 tk.
1000 tk  5 years interest = (1300-1000) = 300 tk.
Ip 1390 tk interest  = (1390-1000) = 390 tk.
1000 tk 300 tk interest 5 years.
1000 "   1  "   "  5/300
1000 "   390   "  5×390/300 = 13/2 or  6.5 years.
Answer: 6.5 year
4) Karim shaheb 56000 tk  he is some tk annual of interest 12% and due tk 10%  he have invested after years total tk 6400 thousand. He Have  does get .how much money ?
Example: 12% rate of interest x invested of money10% rate of interest (5600-x) tk.
100 tk 1 years intereste 12 tk.
1  "  1"   "12/100
X "   1 "  " 12×x/100 = 3x/25 tk.
100 tk 1 years interest 10 tk.
1 "   "         1 "    "  10/100
(5600-x)"  1 "    "  (56000-x) x×10/100
(56000-x)/10
Condition apply , 3x/25 + 56000-x/10 = 6400
Or, 6x+280000-5x/50 = 6400
Or, x +280000 = 320000
Ot, x = 320000-280000
So, x 40000 .

                            Thanks