Secondary school education teaching for math ( compound interest and circle)
We will be learning compound interest so let's go all dear my friend move on details1/ population of the town 80 lakho . So this town growth of population rates 30 and after 3 years rate of population. How may do this people?
Example: population of a town , P= 8000000 Tim ,t= 3 year.
Circle of years, n= 2; growth of population rate, r= 30/1000×100%=33%
There applied growth of population rate formulation
Population C= (1+3/100×1)1×3
= 8000000×(1.03)3 tk
Answer = 8741816 tk.
Example:
2/ 4% rate of interest how much do this compound and circle interest , will be difference 2 year's of 1 tk?.
P = 100 and 4% rates year's Compoun interested = (💯×2×4/💯) 8 tk.
Circle interest = {💯(1+4/100)2 -100} tk.
= {💯×(1.04)2 -100} tk.
=(১০৮.১৬-১০০) টাকা = ৮.১৬
Difference of interest (8.16-8) or 0.16 tk.
P 💯 tk.
1 " " " 100×100/16
= 625 tk.
Example:
3/ rate of annual interest 10 tk. Interest of 500 tk rate of 3 years. How will be interest and circle difference?
There, P= 500 tk.
Time, t= 3 years.
Circle of years,n= 1
Annual interest rate r, =10
Compound interest , = p+i
= p+ p×r×t/100
=(5000+ 5000×10×3/100
=65000 tk
Circle interest
C= p(1+ r/n)n×t
= 5000(1+ 10/100×1)1×3
= 5000×(1.1)3
= 6655 tk.
Difference of compound interest
= (6655-6500)
= 155 tk.
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