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Monday, October 14, 2019

Speed and distance Math

Speed and distance Online education teaching for math   speed and distance                          

Hello viewers I hope that all fine and m fine so today discussion speed of math . BCS and PSC exam shortcut math discussion I will do it. So let's go today's speed shortcut math solution.
At first a example : A boy goes to school with a speed of 200 km / hr it he takes 3 hours then , the distance?

         
            Before we will know

                                  Structure

SL       description.    Symbol.    Question
01.      Speed.               S.                200 km/h
02.       Time.                T.               3 hours
03.       Distance           D.                     ?
Formula D = ST
Solution D= 200×3 = 600 Answers

                       Practice now

1/A man goes to Dhaka a with a speed of 50 km/ hr. If he takes 4 hours then the distance is?
Solution D = 50×4 = 200 Answer.
2/Nazrul crossing street 600 long in 5 minute. His speed in km per hours is?

                             Structure

Formula : D = ST
Solution : 600×5/18 = s×5×60 ⇒s=600/5×60×18/5 km/ hr= 7.2 km/ hr
3/ Dhaka to Chittagong distance 300 km. From Dhaka to start this morning 7 am then arrive to Chittagong 3 pm .how do speed per hour the train?
300= s×8⇒s = 300/8 = 37.5 km/hr
4/ Dhaka to Chittagong distance 600 km.from Dhaka to start the train this morning 7 am . Arrive to Chittagong 1.00 pm. How do speed the train  per hours?
Solution : 600= s×6 ⇒s = 100 km/ hr
4/ Dhaka to Chittagong distance 300 km. From Dhaka to leave this morning 9.00 am and arrive to Chittagong 12.00 
Pm. How do speed the train per hours?
Solution : 300= s×3 ⇒s = 100 km/hr
5/Bimal sprinted 100 metres in 10.61 second. Find his velocity in kilometres / hours. Round to nearest kilometres?
Solution : 100 = s×10.61 ⇒s 9.43 m/ sec = 
9.43×18/5 km/ = 34 km.
6/ GM sharif covers 10.2 km with a speed of 3.4 km/ hr . The time takes cover this distance is?

                         
Structure

Stay fixes distance find out time
Formula : D = ST
Solution : 3.4× T ⇒ T = 3

                    Instant practice

6/ Mr. Habibi covers 30 km with a speed of 10 km/hr . Find the time taken to cover this distance?
Solution : 30 = 10 ×T ⇒ T = 3 Answer
7/ example : Gimu covers a certain distance by car driving at 70 km/ hr and he returns back at the starting point riding on scooter at 55 km/ hr find out his average speed the whole journey?

                        Structure

SL   Description.      Symbol.      Question
01.  Go speed.              X.               70 km/ hr
02.  Back speed.          Y.               55 minute
03. Find out average  s.                   ?
          Speed
Formula  S = 2xy/x+y
Solution : s = 2×70×55/70+55= 61.6
                                         km Answer

8/ A man travels a distance at a rate of 20 mile/ hours  & return at the rate of 30 mile / hours. What is he Avareg speed?
Solution : s = 2×20×30/20+30 = 14 answer.
9/ A man travels from A to B at speed of 20 km/ hr he makes the return journey at speed of 30 km / hr . what was his average speed?
Solution : s = 2×20×30/20+30 = 24 Answer
10/ the distance between Dhaka and bogra is 300 km. A car travels from Dhaka to bogra at 100 km per hours.and return from bogra to Dhaka along the same route at 60 kmper hours. What is the average speed of the round trip?
Solution : 2× 100×60/200+60 = 75 Answer