Relative speed Math solve

Relative speedOnline teach for job preparation of math Relative speed ( part 2)

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1/ Distance Dhaka to Chittagong 185 mile. By a bus from Chittagong per hours 2 hours and 85 mile going to 100 mile . how to speed by bus 50 km.?
⏩Answer : going to Dhaka fromChittagong  needed time t = distance/time = 185/50 = 3.7
85  mile 2 hours going to = (3.7-2) hours
        = 1.7 per hours = ( 1.7×60) = 102 minute
2/ A car speed per hour 25 mile.runing Chittagong from Dhaka.  Another A car speed per hour running Dhaka from Chittagong . Dhaka to Chittagong distance 200 mile. How to running between car After time face to face between car?
⏩Answer : when two car running opposition side
Therefore there Relative speed per hour
 ( 25+15)=  40 mile.
1  hoursspeed go on 40 mile
1   ,,    ,,    1/40
200    ,,     200/40 = 5 hours.
3/ traveling to fast 6 hours Avareg speed 40 km. And second position Avareg speed 60 km. If complete  traveling to car Avareg 55 km. how to traveling time is?
⏩Answer : the car traveling time = t .
       The cat crossing t hour 55 km.
       The car crossing 6 hour =
                       (40×60)=240km
The car (t-6) crossing per hours
                           =  60( t-6) km
Condition apply 240+60( t- 6) = 56 t
Or 240 +60 t - 360 = 55 t
Or 5 t = 120

So t = 24 minute .
4/ house of Karim from Dhaka distance to 356 k.m. he has gone from Dhaka 319 km After bus is out of command so going to by Rickshaw. The speed of bus 22 km. Per hour. And Rickshaw speed 6 km. Per hour. So how did time arrive korim of house?
⏩Answer : Karim go to by bus 319 km
                    By Rickshaw ( 355-319)
                                             = 36 km.
                    Time = distance/ speed
By bus.       = 319/22 = 14 hour 30 minute
By Rickshaw= 36/22 = 6 hours.
Arrive to home time = 14 hour 30 minute+6 hour = 20 hours 30 minute.
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