Online math preparation Relative speed ( train)
we Done relative speed by train. Relative speed very simple and easy solution. So viewers we will try train speed how to knowing Relative speed solution. So
Relative speed
Suppose between two train speed u and v(>v)
1/ When two car or between train move on opposite then Relative speed both equal .
Relative speed = u+v
2/ when two car or train move on same side then Relative speed = u-v
Calculation the speed of a train
A signals post crossings x length and needed t time
A train t time crossings x mitres
So ,, ,, ,, X/t
Train speed = x/t
Y length a object ( when pull and hole, platform.) Others stand a car x length needed t time .
A train t time crossings (x+y). metre Dist.
Metres ,, ,, ,, x+y/t
Example solution
We Done example solution Relative speed A train. Okay .
1 / A train speed per hour 60 metre how do time crossings A lamp post 100 metre train?
Answer: 1 hours = (60×60) second
60 km = (60×1000) metre
(60×1000) crossings time (60×60) second.
1 ,, ,, ,, ,, 60×60/60×100
100 ,, ,, ,, 60×60×100/60×1000
We saw more examples
2/ 50 metres length A train speed per hour 36 km. How do crossings time the train a lamp post ?
Answer: 36 km = (36× 1000) metre =3600 m
1 hour (60×60) = 3600 second.
The train crossings a post and self length
36000 metre needed time 3600 second
1 ,, ,, ,, ,, 3600/36000
50 ,, ,, ,, ,, 3600×50/36000
Answer 5 second.
3/ it hase a plam tree a side on railline . Per hour continue a train speed 45km . The train length is 150 how do crossings time this plam tree?
Answer : (45×1000) metre =45000 metre.
1hour = (60×60) = 3600 second
The train crossings and plam tree 45000 m
3600 second.
1. ,, ,, ,, 3600/45000
150 ,, ,, ,, 3600×150/45000
Answer = 12 second.
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