Time and distance Math suggestions

Distance

Secondary school education teaching for students class time and distance (part 05)

We will be knowing time and distance relative math solutions so let's go come to the point. And details time and distance math policy. Okay friend.

                                  (Time)

⇨60  ( Second)  =  1 (minute)

⇨60  (minute).    =   1 ঘণ্টা (Hour)

⇨24  Hour                       =   1 .(Day)

⇨7   Day                           =   1 (week)

⇨4 week or  28 day       =. 1 (Lunar 

                                                               Month)

                    Name of shuchak

        15                                         15

⇨10.     Peta    1 peta metre = 10.     Metre

        12                                          12

⇨10.     Tera     1 tear gm     = 10.      gm

        9.                                            9

⇨10     geaga      1 geagajhu    =  10 jhul

        6.                                        6

⇨10     mega     1 mega wat  10 wat 

        3.                                           3

⇨10 k.l        1 k.l volt  10 volt

         2.                                               2

⇨ 10  Hector      1 Hector Pascale 10 Pascale

 

    1

⇨10  deka         1 deka Newton 10 Newton

       -1.                                        -1

⇨10  D.c         1 d.c Wham 10 Newton

       -2.                                          -2

⇨10  c.m         1 cm.10 metre

       -3.                                                 -3

⇨10  m.l.           1 m.l ampowar 10 metres

       -6.                                               -6

⇨10 mycro         1 mycro volt  10 volt

        -9.                                              -9

⇨10  nano .          1 nano second 10 second

        -12.                                             -13

⇨10  pk           1 pkf 10   

       -15.                                                -15

⇨10  famto         1 famtoletre 10  Lt.

       -18.                                           -18

⇨10  At           1 at.metre 10.  Metres
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Local and British weight system

Weight system British local and international.weight system British and international

Hello viewers how are ? I hope that all goods
Today I will be discussing international and local

weight system. Okay let's go come to the point.
                             

    weight

                 

local system

⇨5  Tolas            = 1 chatak
⇨16 Chataks      = 1  Seer
⇨40  Seer.           =  1  Mound

                    British system

⇨16  Ounce.          = 1 Pound
⇨28 pound.        = 1Quarter
⇨4 Quater.         = 1 Handar
⇨20 Handar         = 1 British ton

              metres system

⇨100  Kg.       = 1Quintal
⇨1000  Kg.     = 1 Metres
   

                                                             

⇨1 gm. = 0.0022pound = 0.086
                                                          (tola)
⇨1pound = 0.4536  K.g
⇨1 K.g = 2.2  pound = 1.07
                                                                     Seer
⇨1 Seer = 0.93  g.m
⇨1 Mound = 37.2 K.g
⇨1Handar = 1moun 14 seer 7 sotak  = 50.8
                                                        K.g
⇨1  British ton = 27 moun 9 seer = 1
                           Metres ton 16g.m

Next update coming soon.............. waiting
please?


Thanks everybody

Volume and balanced system secondary school Math suggestions

VolumeSecondary school education teaching balanced system volume (part 3)

We are knowing how do it balanced volume system local and international

         (Volume)
⇒1 .(Cubic metre) = 1. ( Stayor)
⇒1 . (Cubic metre) = 💯 (Litres)
⇒1 . (Litres).            = 💯(Cubic cen)
                  Related volume
⇒1 .(Stayor).              = 35.3 (Cubic
                                                                            ft)
⇒1 .(Cubic ft).            = 2867 (Litres)
                          (Liquidm.ca)
                                  British
⇒4 gills.                                      = 1pint (pt)
⇒2pints.                                     = 1quart(qt)
⇒4quart.                                    = 1gullons(gal)
⇒42U.S Gllon                            = 1 Barrel
                                  U.S
⇒1 pint (pt)                               = 1.201 pints
⇒1quart(qt)                              = 1.201quarts
⇒1gallon(gal)                           = 1.201 gallon
                               Metre
⇒1.202 pints.                            = 0.5679 pints
⇒1.201 quarts                          = 1.1359 litres
⇒1.201 gallon                           = 4.5437 litres
                          (D.M.C)
                     British & U.S

     
⇒2gallon.                                  = 1peck
⇒4peck.                                     = 1 bushel
⇒8bushel                                  = 1 quarts
                             U.S & British
⇒1gallon.                                  = 4.5434 Litres
⇒1 peck                                     = 9.0870 litres
⇒1bushel                                  = 36.3477litres
⇒1quarts.                                  = 290.7816 litre
                             British & U.S
⇒4.5434 Litres.                         = 4.404 litres
⇒9.0870 litres.                          = 8.810 litres
⇒36.3477 litres.                        = 35.238 litres
⇒290.7816 litres.                      = 281.904 litres
 So okay Now  stay good everybody

                  Thanks everybody

Area and international balanced system secondary school Math suggestions

Math of Area Secondary school certificate teaching international and local balanced system Area( part 2)

  We will be knowing how do solve it local balanced system. So let's go come to the point. Okay 

                         (Area)

                     (Local Sytem)
⇛1  (Sq.inch).              1 (Ganda)
⇛20(Ganda).                1 (Satak)
⇛16 (Satak).                 1 (Katha)
⇛20 (Katha).                1(Bigha)
             

      (British system)
⇛144  (Sq.inch)      1 (Sq.ft)
⇛9 (Sq.ft)                     1(Sq.yrd)
⇛4840 (Sq.yrd).          1 (Acre)
⇛100 (Decimals).       1(Acre)
(Relationship between British local and metric System)
⇛4 (Gunda)                      1 (Sq.yrd)
⇛5 (Sq.yrd).                      1 (Satak)
⇛80 (Sq.yrd)                720  (Sq.ft)
⇛1 (Decimals).               435.6 (sq.ft)
⇛1600 (Sq.yrd)        1338(Sq.m)
⇛3Biga 4 sotak           4047 (Sq.m)
⇛640 (Acres).          (Sq.miles)
⇛247 (Acres).        1.(Sq.km)
⇛10000 (m✓) 100 (Ayor)=2.47

Measurements math secondary school education

Measurements Secondary school education teaching international system units measurements ( part 1)

Hello viewer's Assalamu alaykum I hope that all fine . Today discussing shall be international system unit .

১/ C.G.S System:⇒
  C.G.S meaning of method, c.m , gm, second it's system of metres

2/ M.KS system
  M.K.S it's meaning km, second. It's metre balanced
3/ F.P.S system
    F.P.S meaning of method fit , pound and second
  C.G.S           M.K.S         F.P.S
 Length       c.m.             fit
 Weight       gm              kg    pound
 Time    =    second
S.I  System:
Stat from  in 1960 in the word same processing all over the country system of (SI) Balanced . it's International System of Units . (S.I) Decided all over the country worldwide in 1982 use of  SI system length , weight,
⇒ meaning of metre
⇒ 1 metre = distance 1 core  divided 1.
Local system: (Local System)
⇒ 12   (Inch)  = 1  (foot)
⇒ 3     (Feet)   = 1 (yard)
⇒1760(Yard)  = 1 (mile)
( British system for measuring land)
⇒ 7.92  (inch)  = 1  ( link)
⇒ 25     (link)   =  1    (Rod)
⇒ 4       (Rod)   =  1 (Chain)
⇒ 10   (Chain) =  1(farling)

⇒ 8 (farlong)= 1 (mile)
(Relationship between British and metric System)
⇒ 1  (inch ) = 2.54 (c.m)
⇒ 39.37 (inch)  = 1 (metre)
⇒ 1        ( mile) = 1.61( k.m)
⇒ 0.62   ( mile) = 1 (k.m)
Balanced of sea  :
          British & US
⇒ 6 Feet = 1 fathom            = 1.8288 metres
⇒ 608 feet = 1 cable.           = 185.313 metres
⇒ 6080 feet = 1 sea(n.m)    = 1853.18 metres
⇒ 60 sea mile = 1 degree
⇒ 360 degree = 1circle
Note
1 Noticeable mile  = 2025 yeard
1 Noticeable mile = 1853.18 metre = 1.85318 km
1 Noticeable = 1.15 mile
Next update Fatchin ..............
Waiting please?

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Compound and interest Math suggestions

Compound and circle

Secondary school education teaching for math ( compound interest and circle)

We will be learning compound interest so  let's go all dear my friend move on details

1/  population of the town 80 lakho . So this town growth of population rates 30 and after 3 years rate of population. How may do this people?
Example: population of a town , P= 8000000  Tim ,t= 3 year.
Circle of years, n= 2; growth of population rate, r= 30/1000×100%=33%
There applied growth of population rate formulation
Population C= (1+3/100×1)1×3
                             = 8000000×(1.03)3 tk
                      Answer  = 8741816 tk.
Example:
2/ 4% rate of interest how much do this compound and circle interest , will be difference 2 year's of 1 tk?.
P = 100 and  4%  rates year's Compoun interested  = (💯×2×4/💯) 8 tk.
Circle interest = {💯(1+4/100)2 -100} tk.
                   = {💯×(1.04)2 -100} tk.
                   =(১০৮.১৬-১০০) টাকা = ৮.১৬
Difference of interest (8.16-8) or 0.16 tk.
P 💯 tk.
1 "    "      "   100×100/16
                  = 625 tk.
Example:
3/ rate of annual interest 10 tk. Interest of 500 tk rate of 3 years. How will be interest and circle difference?
 There, P= 500 tk.
                            Time, t= 3 years.
  Circle of years,n= 1
Annual interest rate r, =10
Compound interest , = p+i
                                       = p+ p×r×t/100
                         

        =(5000+ 5000×10×3/100
                                    =65000 tk
Circle interest
         C= p(1+ r/n)n×t
           = 5000(1+ 10/100×1)1×3
           = 5000×(1.1)3
           = 6655 tk.
Difference of compound interest
           = (6655-6500)
           = 155 tk.

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Compound and cyrcle interest

 compound and simple circle interest

profit P , time t, number of years cycle n  annual interest rate r, 
Cycle capital C= P(1+r/n)n×t 
Cycle interest = cyrcle capital -inteduction amount= C-P 
Cyrcle formula :  P(1+r)n-p
Profit   p , time  n a=r number r .
Cyrcle C =p(1+r)n-p
So  cyrcle interest= C- p = (1+r)n-p
Now we will be checking example. So easy 

and free. Okey we known all details.  

Cyrcle formula

P (1+rate /100) year.
1/ annual 10% interest so solve this 8000 taka cycle interest ?

Example 

First year cycle = capita+ interest

             =(8000+8000×10/100) = 8800 taka
Second year cyrcle =  cyrcle+ interest
            =(8800+8800×10/100)= 9680 taka
Third year cyrcle = cyrcle+interest
            =(9680+9680×10/100)= 20648 taka.

2/  you  have deposited post 10% and deposited amount 15000 so return interest how many interest after 3 years?     

Example :      p, = 15000 taka .  Time t,= 3 years. year of cycle number n= 1
Annual interest rate r = cyrcle C=?
C=P (1+r/n)n×t
=15000(1+10/100×1)1×3 taka.
=15000×(1.1) 3 taka = 19965 taka.
Cycle interest=C-P = (19965-15000) =4965 taka.

Thanks everybody